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c中的string判空
string Count;
Count.empty(); //正确
Count ! null; //错误c中最大最小宏
#include limits.hINT_MAX
INT_MIN
字符串使用发运算将字符加到字符串末尾
string Count;
string str liuda;
Count str[i]; 题目概况 AC代码…题目前置知识
c中的string判空
string Count;
Count.empty(); //正确
Count ! null; //错误c中最大最小宏
#include limits.hINT_MAX
INT_MIN
字符串使用发运算将字符加到字符串末尾
string Count;
string str liuda;
Count str[i]; 题目概况 AC代码
#include iostream
#include cstring
#include limits.h
using namespace std;long long int count 0;
string Count;
int findCount(string str){int bit 1;int nstr.size();for(int i0;in;i){if(str[i]0str[i]9){Count str[i];}else if(!Count.empty()){break;}}if(!Count.empty()){for(int iCount.size()-1;i0;i--){count (Count[i]-0)*bit;bit bit * 10; }
//这里如果题目有负数的话就不能这么做了。if(countINT_MAXcount0){return count;}}return -1;
}int main(){string str;cinstr;int resultfindCount(str);coutresult;return 0;
}
