兼职写好评15元一条seo和sem的概念

Excel表列名称由字母A~Z组成，列字母的规律如下: A、B、C.、AA、AB....AZ、BA、B...ZZZZY、ZZZZ...输入: 输入包含两个列名称字符串，长度均小于等于5。 输出: 输出两个列名称之间共有多少列

样例输入:

AA  AZ

样例输出:

24

代码：

C++：

#include<iostream>
#include<string>
#include<cmath>
using namespace std;
int main() {string s1; cin >> s1;string s2; cin >> s2;int n1 = 0, n2 = 0;for (int i = 0; i < s1.length(); i++) {n1 *= 26;n1 += s1[i] - 'A' + 1;}for (int i = 0; i < s2.length(); i++) {n2 *= 26;n2 += s2[i] - 'A' + 1;}cout << n1 << endl;int res1 = max(n1, n2);int res2 = min(n1, n2);cout << res1 - res2 - 1 << endl;return 0;
}

Python：

class Solution:def main(self):s1 = input()s2 = input()n1 = 0n2 = 0for i in s1:n1 *= 26n1 += ord(i) - 16 + 1for i in s2:n2 *= 26n2 += ord(i) - 16 + 1print(abs(n1 - n2))
if __name__=="__main__":s = Solution()s.main()

Java：

package com.my.gududu;import java.util.*;public class Main {public static void main(String[] args) {Scanner input = new Scanner(System.in);String s1 = input.nextLine();String s2 = input.nextLine();int n1 = 0, n2 = 0;for (int i = 0; i < s1.length(); i++) {n1 *= 26;n1 += s1.charAt(i) - 'A' + 1;}for (int i = 0; i < s2.length(); i++) {n2 *= 26;n2 += s2.charAt(i) - 'A' + 1;}System.out.println(Math.abs(n1 - n2));}
}