verilog实现数码管静态显示

一、任务要求

六个数码管同时间隔0.5s显示0-f。要求：使用一个顶层模块，调用计时器模块和数码管静态显示模块。

二、实验代码

module time_count(input	     clk  ,//50MHz时钟信号input		 rst_n,//复位信号output	reg  flag//一个时钟周期的脉冲信号
);
parameter	 MAX_NUM = 25'd25_000_000;//计数器最大计数值
reg  [24:0]	 cnt                     ; //时钟分频计数器//计数器对时钟计数，每0.5s，输出一个时钟周期脉冲信号
always @(posedge clk or negedge rst_n)beginif(!rst_n)begin//按复位时cnt <= 25'd0;//计数器清零endelse if(cnt == MAX_NUM - 1'b1)begin//如果没到时间cnt <= 0;//计数器正常累计+1endelse begin //否则到时间	cnt <= cnt + 1'b1;end
endalways @(posedge clk or negedge rst_n) beginif(~rst_n) beginflag <= 1'b0;//信号为0endelse if(cnt == MAX_NUM - 1'b1)beginflag <= 1'b1;//信号为0endelse beginflag <= 1'b0;//信号变为1end
endendmodule 

module	seg_led_static(input		      clk     ,input		      rst_n   ,input		      flag    ,output	reg [5:0] sel     ,//数码管位选信号output	reg [7:0] seg  //数码管段选信号
);
parameter   ZERO =  8'b1100_0000,ONE  =  8'b1111_1000,TWO  =  8'b1010_0100,THREE =  8'b1011_0000,FOUR = 8'b1001_1001,FIVE =  8'b1001_0010,SIX =  8'b1000_0010,SEVEN =  8'b1111_1000,EIGHT =  8'b1000_0000,NINE =  8'b1001_0000,A =  8'b1000_1000,B =  8'b1000_0011,C =  8'b1100_0110,D =  8'b1010_0001,E =  8'b1000_0110,F =  8'b1000_1110;
reg [3:0]	num;//数码管显示十六进制数
//控制数码管位选信号(注:低电平有效),选中所有的数码管
always @(posedge clk or negedge rst_n)beginif(!rst_n)//如果按复位键0sel <= 6'b111111;//则默认为高电平else sel <= 6'b000000;//否则为低电平
end
//每次通知信号flag到达时，数码管计数加1
always @(posedge clk or negedge rst_n)beginif(!rst_n)num <=	4'h0;else if(flag)beginif(num < 4'hf)num <= num + 1'h1;else num <= 4'h0;endelse beginnum <= num;end
end
//根据数码管显示的数值，控制段选信号
always @(posedge clk or negedge rst_n)beginif(!rst_n)seg <= 8'b0;else begincase(num)//匹配16进制数4'h0:    seg <= 8'b1100_0000;//匹配到后参考共阳极真值表4'h1:    seg <= 8'b1111_1001;4'h2:    seg <= 8'b1010_0100;4'h3:    seg <= 8'b1011_0000;4'h4:    seg <= 8'b1001_1001;4'h5:    seg <= 8'b1001_0010;4'h6:    seg <= 8'b1000_0010;4'h7:    seg <= 8'b1111_1000;4'h8:    seg <= 8'b1000_0000;4'h9:    seg <= 8'b1001_0000;4'ha:    seg <= 8'b1000_1000;4'hb:    seg <= 8'b1000_0011;4'hc:    seg <= 8'b1100_0110;4'hd:    seg <= 8'b1010_0001;4'he:    seg <= 8'b1000_0110;4'hf:     seg <= 8'b1000_1110;default : seg <= 8'b1100_0000;endcaseend
end
endmodule 

module  top_seg_led_static(input	 	         clk  ,//50MHz系统时钟input		         rst_n,//系统复位信号(低有效)output		[5:0]	 sel  ,//数码管位选output	    [7:0]	 seg//数码管段选
);parameter	MAX_NUM = 25'd25_000_000;// 数码管变化的时间间隔0.5s
wire		add_flag				;// 数码管变化的通知信号
//每隔0.5s产生一个时钟周期的脉冲信号
time_count #(.MAX_NUM(MAX_NUM)) u_time_count(.clk		(clk)  ,//50MHz时钟信号.rst_n		(rst_n),//复位信号.flag		(add_flag)//一个时钟周期的脉冲信号
);
//每当脉冲信号到达时，使数码管显示的数值加1
seg_led_static u_seg_led_static(.clk		(clk)	  ,.rst_n		(rst_n)	  ,.flag	    (add_flag),.sel		(sel)	  ,.seg		(seg)
);
endmodule 

三、仿真代码

`timescale 1ns/1ns
module top_seg_led_static_tb();reg   		 	clk    ;
reg  		 	rst_n  ;
wire    [5:0]	sel	   ;
wire 	[7:0]  	seg    ;
parameter CYCLE = 5'd20;//周期20ns
parameter MAX_NUM = 8'd100;//调小间隔时间100*20ns
always #(CYCLE/2) clk = ~clk;//翻转时钟initial beginclk   = 0		   ;//时钟初始为0rst_n = 0		   ;//复位初始为0#(CYCLE)		   ;//延迟20nsrst_n = 1		   ;//复位置1#(16*MAX_NUM*CYCLE);//显示0-f时间$stop			   ;//停止end 
top_seg_led_static#(.MAX_NUM (MAX_NUM))	u_top_seg_led_static(
.clk  	(clk)  ,//50MHz系统时钟
.rst_n	(rst_n),//系统复位信号(低有效)
.sel  	(sel)  ,//数码管位选
.seg	(seg)	//数码管段选
);
endmodule 

四、仿真结果

五、总结

本文介绍了数码管显示原理，数码管驱动方式等等，并通过代码实现了数码管静态显示