原题链接：

211. 添加与搜索单词 - 数据结构设计

https://leetcode.cn/problems/design-add-and-search-words-data-structure/description/

完成情况：

解题思路：

参考代码：

package 中等题;public class __211添加与搜索单词_数据结构设计 {class WordDictionary {private Trie root;public WordDictionary() {root  = new Trie();}public void addWord(String word) {root.insert(word);}public boolean search(String word) {return dfs(word,0,root);}/**** @param word* @param index* @param curNode* @return*/private boolean dfs(String word, int index, Trie curNode) {if (index == word.length()){return curNode.isEnd();       //curNode.isEnd是去调Trie里面的isEnd属性}char ch = word.charAt(index);if (Character.isLetter(ch)){        //如果已经包含当前字典序开头元素int childIndex = ch - 'a';/**** 下面这行代码。他妈的是什么东西啊？？？？？？？？？？？？**/Trie child = curNode.getChildren()[childIndex];/*********/if (child != null && dfs(word,index+1,child)){return true;}}else {for (int i=0;i<26;i++){Trie child = curNode.getChildren()[i];if (child != null  && dfs(word,index+1,child)){return true;}}}return false;}}//创建一个【字典树】类class Trie{private Trie[] children;private  boolean isEnd;public Trie(){children = new Trie[26];    //字典树链表位26个字母isEnd = false;  //每个都默认看看是不是尾部}/**** @param word*/public void insert(String word){Trie node = this;for (int i=0;i<word.length();i++){char ch = word.charAt(i);int  index = ch -'a';       //用数字带指代26个字母索引if (node.children[index] == null){node.children[index] = new Trie();}node = node.children[index];}node.isEnd = true;}/***  生成对应的默认构造器*/public Trie[] getChildren(){return children;}public boolean isEnd() {return isEnd;}}}