硬件准备

8*8点阵：1个

旋钮电位器：1个

面包板：1块

杜邦线：若干

硬件连线

软件程序

//定义引脚
#define xKnob_pin A0  //x轴旋钮的引脚
#define yKnob_pin A1  //y轴旋钮的引脚
const int row_pin[8] = { 6, 11, 10, 3, 17, 4, 8, 9 };    // 行引脚对应的数组
const int col_pin[8] = { 2, 7, 19, 5, 13, 18, 12, 16 };  // 列引脚对应的数组int pixels[8][8];                                        // 点阵对应的数组//定义变量
unsigned int x_val = -1;//x轴变量
unsigned int y_val = -1;//函数声明
void Init();
void display();
void test();void setup() {Serial.begin(9600);for (int thisRow = 0; thisRow < 8; thisRow++) {pinMode(row_pin[thisRow], OUTPUT);     //设置行引脚为输出模式digitalWrite(row_pin[thisRow], LOW);  //行引脚输出低电平}for (int thisCol = 0; thisCol < 8; thisCol++) {pinMode(col_pin[thisCol], OUTPUT);    //设置列引脚为输出模式digitalWrite(col_pin[thisCol], HIGH);  //列引脚输出高电平}
}void loop() {Init();display();//test();
}void Init(){for (int thisRow = 0; thisRow < 8; thisRow++) {digitalWrite(row_pin[thisRow], LOW);  //行引脚输出低电平}for (int thisCol = 0; thisCol < 8; thisCol++) {digitalWrite(col_pin[thisCol], HIGH);  //列引脚输出高电平}
}void display(){//读取旋钮模拟值，映射为0~7x_val = map(analogRead(xKnob_pin),0,1023,0,7);y_val = map(analogRead(yKnob_pin),0,1023,0,7);Serial.print("x ");Serial.println(x_val);Serial.print("y ");Serial.println(y_val);//根据模拟值决定哪行哪列亮digitalWrite(col_pin[y_val], LOW);digitalWrite(row_pin[x_val], HIGH);
}void test() {for (int thisCol = 0; thisCol < 8; thisCol++) {digitalWrite(col_pin[thisCol], LOW);  //列引脚输出低电平for (int thisRow = 0; thisRow < 8; thisRow++) {digitalWrite(row_pin[thisRow], HIGH);  delay(500);digitalWrite(row_pin[thisRow], LOW);  }digitalWrite(col_pin[thisCol], HIGH);  //列引脚输出高电平}
}

产品展示视频

总结

通过本次实验，我学会了8*8点阵的使用，并复习了旋钮电位器的知识。