名律汇网站建设设计淘宝seo优化是什么
断线重连的整体逻辑是 设备离线后，根据需要决定是否保留pawn，还是设备重连后再重新生成一个，然后是断线重连时的验证方式，最后是playerstate重连后的属性保留
- 重载Playercontroller的PawnLeavingGame,这里是设备断线后，不会删除pawn，根据自己的需求决定是否需要修改，如果不需要保存pawn，没有必要重载该函数。
void AMVNControllerBase::PawnLeavingGame()
{if (GetPawn() != NULL){//GetPawn()->Destroy();//SetPawn(NULL);}
}
2.如果要保留pawn的话，可以重载GameMode的AddInactivePlayer，这个函数原本是保留断线的playerstate的，如果也要保留pawn的话，可以在这个函数里参照保留PlayerState的方式，保存pawn，如果不需要保存pawn，没有必要重载该函数。
void AVTTSGameModeBase::AddInactivePlayer(APlayerState* PlayerState, APlayerController* PC)
{check(PlayerState)UWorld* LocalWorld = GetWorld();// don't store if it's an old PlayerState from the previous level or if it's a spectator... or if we are shutting downif (!PlayerState->IsFromPreviousLevel() && !MustSpectate(PC) && !LocalWorld->bIsTearingDown){APlayerState* const NewPlayerState = PlayerState->Duplicate();APawn* PolicePawn = PC->GetPawn();if (NewPlayerState && PolicePawn){// Side effect of Duplicate() adding PlayerState to PlayerArray (see APlayerState::PostInitializeComponents)GameState->RemovePlayerState(NewPlayerState);// make PlayerState inactiveNewPlayerState->SetReplicates(false);// delete after some timeNewPlayerState->SetLifeSpan(InactivePlayerStateLifeSpan);//设置自动删除的时间PolicePawn->SetLifeSpan(InactivePlayerStateLifeSpan);// On console, we have to check the unique net id as network address isn't validconst bool bIsConsole = !PLATFORM_DESKTOP;// Assume valid unique ids means comparison should be via this methodconst bool bHasValidUniqueId = NewPlayerState->GetUniqueId().IsValid();// Don't accidentally compare empty network addresses (already issue with two clients on same machine during development)const bool bHasValidNetworkAddress = !NewPlayerState->SavedNetworkAddress.IsEmpty();const bool bUseUniqueIdCheck = bIsConsole || bHasValidUniqueId;// make sure no duplicatesfor (int32 Idx = 0; Idx < InactivePlayerArray.Num(); ++Idx){APlayerState* const CurrentPlayerState = InactivePlayerArray[Idx];if ((CurrentPlayerState == nullptr) || CurrentPlayerState->IsPendingKill()){// already destroyed, just remove itInactivePlayerArray.RemoveAt(Idx, 1);InactivePawnArray.RemoveAt(Idx, 1);Idx--;}else if ((!bUseUniqueIdCheck && bHasValidNetworkAddress && (CurrentPlayerState->SavedNetworkAddress == NewPlayerState->SavedNetworkAddress))|| (bUseUniqueIdCheck && (CurrentPlayerState->GetUniqueId() == NewPlayerState->GetUniqueId()))){// destroy the playerstate, then remove it from the trackingCurrentPlayerState->Destroy();InactivePlayerArray.RemoveAt(Idx, 1);InactivePawnArray.RemoveAt(Idx, 1); //保存角色Idx--;}}InactivePlayerArray.Add(NewPlayerState);InactivePawnArray.Add(PolicePawn);// make sure we dont go over the maximum number of inactive players allowedif (InactivePlayerArray.Num() > MaxInactivePlayers){int32 const NumToRemove = InactivePlayerArray.Num() - MaxInactivePlayers;// destroy the extra inactive playersfor (int Idx = 0; Idx < NumToRemove; ++Idx){APlayerState* const PS = InactivePlayerArray[Idx];if (PS != nullptr){PS->Destroy();}}// and then remove them from the tracking arrayInactivePlayerArray.RemoveAt(0, NumToRemove);InactivePawnArray.RemoveAt(0, NumToRemove);}}}
}
- 同理如果需要重新获得之前保留的pawn的话，重载gamemode的restartPlayerAtPlayerStart,默认的话是直接生成新的pawn，如果你想直接使用就的pawn修改响应的逻辑
- 重载时设备的验证，GameMode的FindInactivePlayer函数，默认设备重连时会比较网络的UniqueId，如果一致那么会复制原本的设备的playerstate数据，但是如果你的客户端设备经过重启的话，是会识别成新的客户端，所以根据需要自己去决定是否修改验证方式。
- 重载PlayerState的CopyProperties,将你自定义的变量进行重新复制
以上就是断线重连基本的涉及的函数了，这一切的前提是gamemode必须继承自AGameMode，然后如果你没有保留pawn，或者自己验证重新登录逻辑的话，只需要修改第5条对应的内容就可以实现断线重连了